A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of $30 m s^{- 1}$ and rebounds with a velocity of $20 m s^{- 1}$ in the opposite direction. The impulse of the force exerted by the ball on the bat is

0.5 Ns

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.0 Ns

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 Ns

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50 Ns

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 25 Ns
Impulse = change in momentum
$= m u - m (- υ)$
$= m (u + υ) = 0.5 \times (30 + 20) = 25 N s$
Hence, the correct choice is (c).

Suggest Corrections

Similar questions

Q. A cricket ball of mass 500 gm strikes a bat normally with a velocity 30 m/s and rebounds with a velocity 20 m/s in the opposite direction. The impulse of the force exerted by the ball on the bat is:

Q. A ball of mass

0.2 k g

is thrown against the wall

,

the ball strikes the wall normally with velocity of

30 m / s

sand rebounds with velocity of

20 m / s .

Calculate the impulse of the force exerted by the ball on the wall

Q. A ball of mass

0.1

kg strikes a wall normally with a speed of

30 m s^{- 1}

and rebounds with a speed of

20 m s^{- 1}

. The impulse of the force exerted by the wall on the ball is

Q. A 100 g ball moving with a velocity of 20 m/s returns in opposite direction with a velocity of 30 m/s after striking a bat. Find the impulse.

A cricket ball of mass $150 g$ is moving with a velocity $12 m s^{- 1}$ and is hit by a bat so that the ball is turned back with a velocity of $20 m s^{- 1}$ . If the duration of contact between the ball and bat is $0.01 s$ , find the impulse and the average force exerted on the ball by the bat.

Join BYJU'S Learning Program

A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of 30ms−1 and rebounds with a velocity of 20ms−1 in the opposite direction. The impulse of the force exerted by the ball on the bat is

The correct option is C 25 NsImpulse = change in momentum =mu−m(−υ) =m(u+υ)=0.5×(30+20)=25 Ns Hence, the correct choice is (c).

A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of $30 m s^{- 1}$ and rebounds with a velocity of $20 m s^{- 1}$ in the opposite direction. The impulse of the force exerted by the ball on the bat is

The correct option is C 25 Ns
Impulse = change in momentum
$= m u - m (- υ)$
$= m (u + υ) = 0.5 \times (30 + 20) = 25 N s$
Hence, the correct choice is (c).