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Question

A ball of mass (m) 0.5 kg is attached to the end of a string having length (L) 0.5 m . The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324 N. The maximum value of angular velocity of ball (in rad s1) is
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Solution

T=mlω2
324=0.5ω2×(0.5)$
ω2=324×4
ω=18×2=36 radian/s

Maximum angular velocity of ball, ω=36 radian /s

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