Question

A ball of mass (m) 0.5 kg is attached to the end of a string having length (l) 0.5m. The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324 N. The maximum possible value of angular velocity of ball (in rad/s) is

• A. 9
• B. 18
• C. 27
• D. 36

Answer 1

The correct option is D

36

Let $T$ be the tension in the string.
Now, $Tsin\theta =m{\omega }^2\left(lsin\theta \right)\Rightarrow T=m{\omega }^{2}l$
Substituting the given values, we get $\omega =36rad/s$