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Question

A ball of mass m is projected with velocity u making an angle θ with the horizontal. What is its angular momentum at the highest point?


A
mu2gsin2θcosθ
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B
mu2gsinθcos2θ
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C
mu32gsinθcos2θ
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D
mu32gsin2θcosθ
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Solution

The correct option is D mu32gsin2θcosθ
L=m×v×r
r=perpendicular distance
Height of the projectile =Hmax=u2sin2θ2g
Velocity at heighest point VHZ=ucosθ
L=m×(ucosθ)×(u2sin2θ2g)

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