A ball of mass 'm' moves with speed 'v' and it strikes normally with a wall and reflects back.If its time of contact with wall is t, then find force exerted by ball on the wall

\frac{2 m v}{t}

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\frac{m v}{t}

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m v t

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\frac{m v}{2 t}

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Solution

The correct option is A $\frac{2 m v}{t}$
The linear momentum of the ball before collision was $p_{1} = m v$
after collision its direction was got $r e v e r s e d$ but with same $s p e e d$ so the new momentum will be $p_{2} = - m v$
so the change in momentum will be $Δ p = p_{2} - p_{1} = - m v - m v = - 2 m v$
So the force exerted will be $F = \frac{Δ p}{t i m e} = \frac{- 2 m v}{t}$
whose $m a g n i t u d e$
is $\frac{2 m v}{t}$ so option A is correct.

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