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Question

A ball of mass m moving with speed v0 bounces back and forth between two massive stationary walls separated by a distance . The collisions are perfectly elastic and effect of gravity is to be neglected. One of the walls starts moving slowly towards the other wall with speed v1(v1<v0) find the velocity of ball when the distance between the walls has been reduced /2 to (Assume mass of wall >>m


A
data insufficient
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B
v0
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C
2v0
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D
v0 +2v1
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Solution

The correct option is C 2v0
During each collision with wall A, velocity of the ball increases by 2v1 but velocity of wall remains unchanged.
2xv=(Δx)v1but Δv=2v1
ΔxΔv=xv;
or k/2dxx=vv0dvvv=2v0
Final Answer: (c)

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