A ball thrown by a boy is caught by another after $2$ sec some distance away in the same level.If the angle of projection is $30$ the velocity of projection is

18.0

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19.6

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20.0

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18.6

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Solution

The correct option is B $19.6$
$T = \frac{2 u s i n θ}{g}$
$u = T \times \frac{g}{2 s i n θ}$
$u = 2 \times \frac{9.8}{2} \times s i n 30$
Hence, $U = 19.6 m / s$

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A ball thrown by a boy is caught by another after 2sec some distance away in the same level.If the angle of projection is 30 the velocity of projection is

The correct option is B 19.6T=2usinθgu=T×g2sinθu=2×9.82×sin30Hence, U=19.6m/s

A ball thrown by a boy is caught by another after $2$ sec some distance away in the same level.If the angle of projection is $30$ the velocity of projection is

The correct option is B $19.6$
$T = \frac{2 u s i n θ}{g}$
$u = T \times \frac{g}{2 s i n θ}$
$u = 2 \times \frac{9.8}{2} \times s i n 30$
Hence, $U = 19.6 m / s$