A ball thrown vertically upwards with a speed of 19.6 m/s from the top of a tower returns to the earth in 6s. Find the height of tower. What is a=-g in this case?

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Solution

From This taking upward direction to be positive

It is given that,

u=19.6m/s

t=6s

a=-g=-9.8m/s^2

Displacement of the ball=-h

Applying s=ut+(at^2)/2

-h=19.6(6)+(-9.8)(36)/2

h=58.8m

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A ball thrown vertically upwards with a speed of 19.6 m/s from the top of a tower returns to the earth in 6s. Find the height of tower. What is a=-g in this case?

From This taking upward direction to be positive It is given that, u=19.6m/s t=6s a=-g=-9.8m/s^2 Displacement of the ball=-h Applying s=ut+(at^2)/2 -h=19.6(6)+(-9.8)(36)/2 h=58.8m

From This taking upward direction to be positive

It is given that,

u=19.6m/s

t=6s

a=-g=-9.8m/s^2

Displacement of the ball=-h

Applying s=ut+(at^2)/2

-h=19.6(6)+(-9.8)(36)/2

h=58.8m