You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Oblique Collision

A ball with v...

Question

A ball with velocity $9 m / s$ collides with another similar stationary ball. After the collision the two balls move in directions making an angle of $30^{o}$ with the initial direction. The ratio of the speeds of balls after the collision will be :

\frac{v_{1}}{v_{2}} = 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{v_{1}}{v_{2}} > 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{v_{1}}{v_{2}} < 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{v_{1}}{v_{2}} = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{v_{1}}{v_{2}} = 1$
Let $v_{1}$ and $v_{2}$ be the velocities of above and below particles respectively, as there is no external force .momentum is conserved.
conserving the momentum in vertical direction,

$m v_{1} sin (30) = m v_{2} sin (30)$

$\Rightarrow v_{1} = v_{2}$

$\Rightarrow \frac{v_{1}}{v_{2}} = 1$

Suggest Corrections

Similar questions

Q. A ball moving with velocity of

9 m / s

collides with another similar stationary ball. After the collision both the balls move in directions making an angle of

30^{o}

with the initial direction. After the collision their speed will be?

A ball moving with a velocity of 9 m/sec collides with another similar stationary ball. After the collision both the balls move in directions making an angle of 30° with the initial direction. After the collision, their speed will be:-

Q. Two balls of masses

m_{1} and m_{2}

such that (

m_{2} >> m_{1}

) are moving with initial velocities

v_{1} and v_{2}

respectively towards each other. The final velocity of

m_{2}

after collision will be [Assume collision to be perfectly elastic]

Q. Particle

A

of mass

m_{1}

moving with velocity

(\sqrt{3}^i +^j) m s^{- 1}

collides with another partice

B

of mass

m_{2}

which is at rest initially. Let

_{1}

and

_{2}

be the velocities of particles

A

and

B

after collision respectively. If

m_{1} = 2 m_{2}

and after collision

_{1} = (^i + \sqrt{3}^j) m s^{- 1},

the angle between

_{1}

and

_{2}

is :

Q. A spherical ball

A

of mass

4 k g

, moving along a straight line strikes another spherical ball

B

of mass

1 k g

at rest. After the collision,

A

and

B

move with velocities

v_{1} m s^{- 1}

and

v_{2} m s^{- 1}

respectively making angles of

30^{\circ}

and

60^{\circ}

with respect to the original direction of motion of

A

. The ratio

\frac{v_{1}}{v_{2}}

will be:

Join BYJU'S Learning Program

A ball with velocity 9 m/s collides with another similar stationary ball. After the collision the two balls move in directions making an angle of 30o with the initial direction. The ratio of the speeds of balls after the collision will be :

The correct option is A v1v2=1Let v1 and v2 be the velocities of above and below particles respectively, as there is no external force .momentum is conserved.conserving the momentum in vertical direction,mv1sin(30)=mv2sin(30)⇒v1=v2⇒v1v2=1

A ball with velocity $9 m / s$ collides with another similar stationary ball. After the collision the two balls move in directions making an angle of $30^{o}$ with the initial direction. The ratio of the speeds of balls after the collision will be :