A balloon is filled with 2 L of air at 300 K. will be the volume of the balloon at 600 K.

2 L

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3 L

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4 L

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Solution

The correct option is C 4 L
This question deals with changes in volume of a gas with change in temperature, with the pressure remaining constant.

This is dealt by Charles' law which states that pressure remaining constant, volume of a gas is directly proportional to its temperature.

i.e $V$ α $T$ or $\frac{V}{T} = k$ , where $k$ is a constant.

Thus, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ , where $V_{1} a n d T_{1}$ refer to the initial volume and temperature respectively where as $V_{2} a n d T_{2}$ refer to the final volume and temperature respectively.

$V_{1}$ = 2 L, $V_{2}$ = ?

Therefore, $V_{2} = \frac{V_{1} \times T_{2}}{T_{1}}$ = $\frac{2 \times 600}{300}$ = 4 L

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