Question

A balloon is filled with 2 L of air at 300 K. will be the volume of the balloon at 600 K.

• A. 2 L
• B. 3 L
• C. 4 L

Answer 1

The correct option is C 4 L

This question deals with changes in volume of a gas with change in temperature, with the pressure remaining constant.

This is dealt by Charles' law which states that pressure remaining constant, volume of a gas is directly proportional to its temperature.

i.e $V$ α $T$ or $\frac{V}{T}=k$, where $k$ is a constant.

Thus, $\frac{V_1}{T_1}=\frac{V_2}{T_2}$, where $V_{1}and{T}_1$ refer to the initial volume and temperature respectively where as $V_{2}and{T}_2$ refer to the final volume and temperature respectively.

$V_1$ = 2 L, $V_2$ = ?

Therefore, $V_2=\frac{V_1\times T_2}{T_1}$= $\frac{2\times 600}{300}$ = 4 L