wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A bar AB of diameter 40 mm and 4 m long is rigidly fixed at its ends. A torque 600 N-m is applied at a section of the bar, 1 m from end A. The fixing couples TA and TB at the supports A and B, respectively are

A
200 N-m and and 400 N-m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
300 N-m and 150 N-m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
450 N-m and 150 N-m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
300 N-m and 100 N-m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 450 N-m and 150 N-m

The fixing couple TA and TB at A and B respectively is given by

TA=T0×ba+b

=600×31+3=450Nm

TB=T0×aa+b

=600×14=150 Nm

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Strength of Shafts in Torsion
STRENGTH OF MATERIALS
Watch in App
Join BYJU'S Learning Program
CrossIcon