A bar is subjected to equal and opposite forces as shown in the figure- PQRS is a plane making angle - with the cross-section of the bar- If the area of cross-section be - A - then what is the tensile stress on PQRSA- F-AB- F cos-AC- F-A cos-A

The correct option is D As tensile stress = Normal force/Area=F_N/A_N and here A_N= ( A/cosθ ), F_N=Normal force=F cos θ So, Tensile stress = Fcosθ/A/cosθ=F ...

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Standard XII

Physics

Longitudinal Stress

A bar is subj...

Question

A bar is subjected to equal and opposite forces as shown in the figure. PQRS is a plane making angle $θ$ with the cross-section of the bar. If the area of cross-section be ‘A’, then what is the tensile stress on PQRS

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Solution

The correct option is C

As tensile stress = $\frac{N o r m a l f o r c e}{A r e a} = \frac{F_{N}}{A_{N}}$
and here $A_{N} = (\frac{A}{c o s θ}), F_{N} = N o r m a l f o r c e = F c o s θ$
So, Tensile stress $= \frac{F c o s θ}{\frac{A}{c o s θ}} = \frac{F c o s^{2} θ}{A}$

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A bar is subjected to equal and opposite forces as shown in the figure. PQRS is a plane making angle θ with the cross-section of the bar. If the area of cross-section be ‘A’, then what is the tensile stress on PQRS

The correct option is C As tensile stress = NormalforceArea=FNAN and here AN=(Acosθ),FN=Normal force=F cos θ So, Tensile stress =FcosθAcosθ=Fcos2θA

A bar is subjected to equal and opposite forces as shown in the figure. PQRS is a plane making angle $θ$ with the cross-section of the bar. If the area of cross-section be ‘A’, then what is the tensile stress on PQRS

The correct option is C

As tensile stress = $\frac{N o r m a l f o r c e}{A r e a} = \frac{F_{N}}{A_{N}}$
and here $A_{N} = (\frac{A}{c o s θ}), F_{N} = N o r m a l f o r c e = F c o s θ$
So, Tensile stress $= \frac{F c o s θ}{\frac{A}{c o s θ}} = \frac{F c o s^{2} θ}{A}$