Question

A bar is subjected to equal and opposite forces as shown in the figure. PQRS is a plane making angle $\theta$ with the cross-section of the bar. If the area of cross-section be ‘A’, then what is the shearing stress on PQ

• A. $\frac{F}{Acos\theta }$
  
• B. $\frac{Fsin2\theta }{2A}$
  
• C. $\frac{F}{2Asin2\theta }$
  
• D. $\frac{Fcos\theta }{A}$

Answer 1

The correct option is B $\frac{Fsin2\theta }{2A}$


Shear stress $=\frac{Tangentialforce}{Area}=\frac{Fsin\theta }{\left(\frac{A}{cos\theta }\right)}=\frac{Fsin\theta cos\theta }{A}=\frac{Fsin2\theta }{2A}$