Question

A bar is subjected to equal and opposite forces as shown in the figure. PQRS is a plane making angle $\theta$ with the cross-section of the bar. If the area of cross-section be ‘A’, then when is the tensile stress maximum

• A. $\theta =0^{\circ }$
• B. $\theta ={30}^{\circ }$
• C. $\theta ={45}^{\circ }$
• D. $\theta ={90}^{\circ }$

Answer 1

The correct option is A $\theta =0^{\circ }$

Tensile stress $=\frac{Fco{s}^2\theta }{A}$. It will be maximum when $co{s}^2\theta =max.i.e.cos\theta =1\Rightarrow \theta =0^{\circ }$