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Question

# A bar magnet of magnetic moment 1.5 J T−1 lies aligned with the direction of a uniform magnetic field of 0.22 T. (a) What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment: (i) normal to the field direction, (ii) opposite to the field direction? (b) What is the torque on the magnet in cases (i) and (ii)?

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Solution

## (a)Magnetic moment, M = 1.5 J T−1 Magnetic field strength, B = 0.22 T (i)Initial angle between the axis and the magnetic field, θ1 = 0° Final angle between the axis and the magnetic field, θ2 = 90° The work required to make the magnetic moment normal to the direction of magnetic field is given as: (ii) Initial angle between the axis and the magnetic field, θ1 = 0° Final angle between the axis and the magnetic field, θ2 = 180° The work required to make the magnetic moment opposite to the direction of magnetic field is given as: (b)For case (i): ∴Torque, For case (ii): ∴Torque,

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