A magnet of magnetic moment $2 J T^{- 1}$ is aligned in the direction of magnetic field of 0.1 T. What is the net work done to bring the magnet normal to the magnetic field

0.1 J

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0.2 J

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1 J

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2 J

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Solution

The correct option is B 0.2 J
$W = M B (1 - c o s θ) = 2 \times 0.1 \times (1 - c o s 90^{\circ}) = 0.2 J$

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Similar questions

Q. A magnet of magnetic moment

2 J T^{- 1}

is aligned in the direction of magnetic field of 0.1 T. What is the net work done to bring the magnet normal to the magnetic field

A bar magnet of magnetic moment 1.5 J T⁻¹ lies aligned with the direction of a uniform magnetic field of 0.22 T.

(a) What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment: (i) normal to the field direction, (ii) opposite to the field direction?

(b) What is the torque on the magnet in cases (i) and (ii)?

Q. A bar magnet of magnetic moment 6 J/T is aligned at

60^{0}

with a uniform external magnetic field of 0.44 T. Calculate (a) the work done in turning the magnet to align its magnetic moment (i) normal to the magnetic field, (ii) opposite to the magnetic field, and
(b) the torque on the magnet in the final orientation
in case (ii).

A bar magnet of magnetic moment 1.5 J/T is aligned with the direction of a uniform magnetic field of 0.22 T. The work done in turning the magnet so as to align its magnetic moment opposite to the field and the torque acting on it in this position are respectively :

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A magnet of magnetic moment 2JT−1 is aligned in the direction of magnetic field of 0.1 T. What is the net work done to bring the magnet normal to the magnetic field

The correct option is B 0.2 JW=MB(1−cos θ)=2×0.1×(1−cos 90∘)=0.2 J

A magnet of magnetic moment $2 J T^{- 1}$ is aligned in the direction of magnetic field of 0.1 T. What is the net work done to bring the magnet normal to the magnetic field

The correct option is B 0.2 J
$W = M B (1 - c o s θ) = 2 \times 0.1 \times (1 - c o s 90^{\circ}) = 0.2 J$