A bar magnet when placed at an angle of 30o to the direction of Magnetic field induction 5 - 10-4T experiences a moment of couple of 25 - 10-6 Nm- If the length of the Magnet is 5 cm- its pole strength is -

The correct option is C 2Am B=5× 10^ 4T , #160; τ=25× 10^ 6Nm , #160; l=5 m , θ =30^o M=pl p= pole strength τ=m× B ...

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Byju's Answer

Standard XII

Physics

Current Loop Is a Magnet?

A bar magnet ...

Question

A bar magnet when placed at an angle of $30^{o}$ to the direction of Magnetic field induction $5 \times 10^{- 4} T$ experiences a moment of couple of $25 \times 10^{- 6} N m$ . If the length of the Magnet is $5 c m$ , its pole strength is :

2 \times 10^{- 2} A m

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5 \times 10^{- 2} A m

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2 A m

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5 A m

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Solution

The correct option is C $2 A m$
$B = 5 \times 10^{- 4} T$ , $τ = 25 \times 10^{- 6} N m$ , $l = 5 m$ , $θ = 30^{o}$
$M = p l$
$p =$ pole strength
$τ = m \times B$
$τ = m B sin θ$
$25 \times 10^{- 6} = p l \frac{1}{2} \times B$
$p = 2 A m$

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A bar magnet when placed at an angle of 30o to the direction of Magnetic field induction 5×10−4T experiences a moment of couple of 25×10−6Nm. If the length of the Magnet is 5cm, its pole strength is :

The correct option is C 2AmB=5×10−4T, τ=25×10−6Nm, l=5m, θ=30oM=plp=pole strengthτ=m×Bτ=mBsinθ25×10−6=pl12×Bp=2Am

A bar magnet when placed at an angle of $30^{o}$ to the direction of Magnetic field induction $5 \times 10^{- 4} T$ experiences a moment of couple of $25 \times 10^{- 6} N m$ . If the length of the Magnet is $5 c m$ , its pole strength is :

The correct option is C $2 A m$
$B = 5 \times 10^{- 4} T$ , $τ = 25 \times 10^{- 6} N m$ , $l = 5 m$ , $θ = 30^{o}$
$M = p l$
$p =$ pole strength
$τ = m \times B$
$τ = m B sin θ$
$25 \times 10^{- 6} = p l \frac{1}{2} \times B$
$p = 2 A m$