Question

A bar of $2.0m$ long makes an angle of ${30}^o$ with the horizontal. A vertical force of $40N$ is applied $0.4m$ from the upper end. Calculate the torque due to this force about each end.

Answer 1

torque about upper end=$40\times 0.4\cos {30}^0=8\sqrt{3}$Nm

torque about lower end=$40\times 1.6\cos {30}^0=32\sqrt{3}$Nm