A bar of 75 mm diameter is reduced to 73 mm by a cutting tool while cutting orthogonally- If the rake angle is 15- and shear angle is 0-3328 radian- The mean length of cut chip is mm-

76.137 Length of uncut chip,l=π/2(D_i+D_f) Length of uncut chip, l=π (75+73)/2=232.48 mm Φ=0.3328 radian = 19.068^∘ tan 19.068^∘ =r cos15^∘/1 r sin 15^∘ r=l_c/ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Production

Abbreviation Used in Analysis of Metal Cutting & Cutting Ratio

A bar of 75 m...

Question

A bar of 75 mm diameter is reduced to 73 mm by a cutting tool while cutting orthogonally. If the rake angle is $15^{\circ}$ and shear angle is 0.3328 radian. The mean length of cut chip is _____ mm.

76.137

Open in App

Solution

The correct option is A 76.137
76.137

Length of uncut chip, $l = \frac{π}{2} (D_{i} + D_{f})$
Length of uncut chip, $l = \frac{π (75 + 73)}{2} = 232.48 m m$
$Φ = 0.3328 r a d i a n = {19.068}^{\circ}$
$t a n {19.068}^{\circ} = \frac{r c o s 15^{\circ}}{1 - r s i n 15^{\circ}}$
$r = \frac{l_{c}}{l}$
$0.3275 = \frac{l_{c}}{232.48}$
$l_{c} = 76.137 m m$

Suggest Corrections

Similar questions

Q. A bar of 75 mm diameter is machined to reduce its diameter by orthogonal cutting. If the length of the cut chip is 73.5 mm and rake angle is

15^{\circ}

, the shear plane angle is

Q. A bar of 75 mm diameter is machined to reduce its diameter by orthogonal cutting. If the length of the cut chip is 73.5 mm and rake angle is

15^{\circ},

the shear plane angle is

Q. In orthogonal turning of a low carbon steel bar of diameter

150 m m

uncoated carbide tool the cutting velocity is

90 m / m i n

. The feed is

0.24 m m / r e v

and the depth of cut is

2 m m

. The chip thickness obtained is

0.48 m m

. If the orthogonal rake angle is zero and the principal cutting edge angle is

90^{o}

, the shear angle in degree is

Q. Common Data:
An orthogonal operation is carried out at

20 m / m i n

cutting speed, using a cutting tool of rake angle

15

degree. The chip thickness is

0.4 m m

and uncut chip thickness is

0.2 m m

The shear angle (in degrees) is

Q. In a turning process using orthogonal tool geometry, a chip length of 100 mm is obtained for an uncut chip length of 250 mm. The cutting conditions are cutting speed = 30 m/min, rake angle = 20°.
The shear plane angle is degrees (round off to one decimal place).

Join BYJU'S Learning Program

A bar of 75 mm diameter is reduced to 73 mm by a cutting tool while cutting orthogonally. If the rake angle is 15∘ and shear angle is 0.3328 radian. The mean length of cut chip is _____ mm. 76.137

The correct option is A 76.13776.137 Length of uncut chip,l=π2(Di+Df) Length of uncut chip, l=π(75+73)2=232.48mm Φ=0.3328radian=19.068∘ tan19.068∘=rcos15∘1−rsin15∘ r=lcl 0.3275=lc232.48 lc=76.137mm

A bar of 75 mm diameter is reduced to 73 mm by a cutting tool while cutting orthogonally. If the rake angle is $15^{\circ}$ and shear angle is 0.3328 radian. The mean length of cut chip is _____ mm.

76.137