Question

A bar of circular cross-section of diameter D is subjected to a torque T at B as shown in the figure given below


What is the angle of twist at A?

• A. Same as that at B
• B. Zero
• C. Twice as that at B
• D. Half as that at B

Answer 1

The correct option is A Same as that at B

${\theta }_B=\frac{TL}{2GJ}$

${\theta }_A=\sum \frac{TL}{GJ}=\frac{TL}{2GJ}+0=\frac{TL}{2GJ}$

So angle of twist at A will be equal to that at B, because there is no torque between A and B.