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Question

A barbell of mass 5 kg is raised to a height of 3 m above the ground. Calculate the work done by the boy. Take acceleration due to gravity g=10 ms2.

  1. 150 J
  2. - 150 J
  3. -300 J
  4. 300 J


Solution

The correct option is A 150 J
Mass of barbell, m = 5 kg
Height of lift, h = 3 m
Force require to lift the barbell = Weight of the barbell
Weight of the barbell =m×g
=5×10=50 N
Work done by boy, W=Force×Displacement
=50×3=150 Nm or J
Work done is positive as both force and displacemnet are in the same direction.

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