A batsman hit back a ball straight in the direction of the bowler without changing its initial speed of 12ms−1. If the mass of the ball is 0.15kg, the impulse imparted to the ball is
A
2.8Ns
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B
3.6Ns
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C
3.9Ns
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D
4.2Ns
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Solution
The correct option is B3.6Ns
Impulse = change in linear momentum .
initial momentum of ball=mu
=0.15×12=1.8kg.m/sec
final momentum of ball =−mu
=−0.15×12=−1.8kgm/sec
now,
change in momentum of ball =final −initial
=−1.8−1.8=−3.6kgm/sec
so,
change in momentum of bat =−change in momentum of ball
change in momentum of bat =3.6kgm/s
now,
impulse imparted to ball =change in momentum of bat =3.6kgm/s=3.6Ns