A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12ms−1. If the mass of the ball is 0.15kg the magnitude of the impulse imparted to the ball is
A
36kgm/s
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B
3.6kgm/s
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C
0.36kgm/s
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D
0.03kgm/s
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Solution
The correct option is B3.6kgm/s
Impulse = Change in linear momentum .
Initial momentum of ball =mu
=0.15×12=1.8kg.m/sec
Final momentum of ball =−mu
=−0.15×12=−1.8kgm/sec
Now,
Change in momentum of ball = Final − Initial
=−1.8−1.8=−3.6kgm/sec
So,
Change in momentum of bat =− change in momentum of ball
Change in momentum of bat =3.6kgm/s
Now,
Impulse imparted to ball = Change in momentum of bat =3.6kgm/s