Question

A batsman scores runs in 10 innings as 38, 70, 48, 34, 42, 55, 63, 46, 54 and 44. The mean deviation about mean is
(a) 8.6
(b) 6.4
(c) 10.6
(d) 7.6

Answer 1

Disclaimer: No option is matching the answer.


$$\begin{gathered} N=10 \\ \overline{X}=\frac{38+70+48+34+42+55+63+46+54+44}{10} \\ =\frac{494}{10} \\ =49.4 \end{gathered}$$

xi	di =$\left|x_i-49.4\right|$
34	15.4
38	11.4
42	7.4
44	5.4
46	3.4
48	1.4
54	4.6
55	5.6
63	13.6
70	20.6
	$\sum _{i=}^n{d}_i=88.8$

$$\begin{gathered} \mathrm{Mean}\mathrm{deviation}\mathrm{from}\mathrm{the}\mathrm{mean}=\frac{88.8}{10} \\ =8.88 \end{gathered}$$