A battery is charged at a potential of 15V in 8h when the current flowing is 10A. The battery on discharge supplies a current of 5A for 15h. The mean terminal voltage during discharge is 14V. The watt-hour efficiency of battery is
A
80%
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B
90%
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C
87.5%
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D
82.5%
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Solution
The correct option is D87.5% Power of battery, when charged is given by P1=V1I1 Electrical energy dissipated is given by E1=P1t1 E1=V1I1t1=15×10×8=1200Wh Similarly, the electrical energy dissipated during the discharge of battery is given by E2=V2I2t2=14×5×15=1050Wh Hence, watt-hour efficiency of the battery ⇒η=E2E1×100=0.875×100=87.5%