A battery is supplying power to a tape-recorder by cable of resistance of 0.02Ω. If the battery is generating 50W power at 5V, then power received by tape-recorder is:- (neglect internal resistance of battery)
A
50W
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B
45W
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C
30W
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D
48W
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Solution
The correct option is D48W P=VI
⇒I=10A
power loss in the cable =I2R=100×0.02=2W
Hence, power supplied to the tape− recorder is 48W