Question

While connecting $6$ cells in a battery in series, in a tape recorder, by mistake one cell is connected with reverse polarity. If the effective resistance of load is $24$ ohm and internal resistance of each cell is one ohm and emf $1.5V$, the current delivered by the battery is

• A. $0.1A$
• B. $0.2A$
• C. $0.3A$
• D. $0.4A$

Answer 1

The correct option is B $0.2A$

Applying KVL to the loop
$4E=I[R+6r]$
$4\times 1.5=I\left[30\right]$
$I=\frac{6}{30}$
$I=\frac{1}{5}=0.2A$