Question

Five cells of emf 1.5V and internal resistance 0.2 ohm are connected in series. The maximum current that can be delivered is

• A. 7.5A
• B. 1.5A
• C. 4A
• D. 2A

Answer 1

Answer: (A)

7.5A

$E_{eff}=1.5\times 5$
$=$ 7.5 V
$r_{eff}=0.2\times 5$
$=1\Omega$
for maximum current flow load resistance $=0\Omega$
$\Rightarrow E_{eff}=I{r}_{eff}$
$\Rightarrow I=\frac{7.5}{1}=7.5A$