A battery of 10 V is connected to a condenser of capacity 100 mF. The battery is removed and the condenser is connected to an identical uncharged condenser. It is found that the charge distributes equally on these two condensers. The common potential of the system is?

10V

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20V

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2.5V

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Solution

The correct option is B 5V
Common potential $V = \frac{C_{1} V_{1} + C_{2} V_{2}}{C_{1} + C_{2}} V = \frac{(100 \times 10 + 0)}{2 C_{1}} 10^{- 3} = \frac{1}{2 \times 100 \times 10^{- 3}} = \frac{1000}{200} = 5 V$ .

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A battery of 10 V is connected to a condenser of capacity 100 mF. The battery is removed and the condenser is connected to an identical uncharged condenser. It is found that the charge distributes equally on these two condensers. The common potential of the system is?

The correct option is B 5VCommon potential V=C1V1+C2V2C1+C2V=(100×10+0)2C110−3=12×100×10−3=1000200=5V.

The correct option is B 5V
Common potential $V = \frac{C_{1} V_{1} + C_{2} V_{2}}{C_{1} + C_{2}} V = \frac{(100 \times 10 + 0)}{2 C_{1}} 10^{- 3} = \frac{1}{2 \times 100 \times 10^{- 3}} = \frac{1000}{200} = 5 V$ .