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Question

A battery of 10 V is connected to a condenser of capacity 100 mF. The battery is removed and the condenser is connected to an identical uncharged condenser. It is found that the charge distributes equally on these two condensers. The common potential of the system is?

A
10V
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B
5V
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C
20V
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D
2.5V
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Solution

The correct option is B 5V
Common potential V=C1V1+C2V2C1+C2V=(100×10+0)2C1103=12×100×103=1000200=5V.

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