Question

A battery of 12V is connected in series with resistors of 0.2 Ω, 0.3 Ω, 0.5 Ω and 5 Ω. How much current would flow through the 5-Ω resistor?

• A. 1 A
• B. 2 A
• C. 0.5 A
• D. None of these

Answer 1

The correct option is B

2 A

R(equivalent) = .2 + .3 +.5 + 5 = 6 Ω

I = $\frac{12}{6}$ = 2 A

In series, same current flows through all the resistors.

Hence, 2 A current will flow through 5 Ω resistor.