A battery of 9 V is connected in series with resistors of 0.2W, 0.3W, 0.4W, 0.5W and 12W. How much current would flow through the 12W resistor? (Give the answer in A to 2 decimal places)

0.67

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0.76

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0.87

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0.90

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Solution

The correct option is A
0.67

Since all the resistors are in seies, equivalent resistance,

Rs = 0.2 W + 0.3 W + 0.4 W + 0.5 W + 12 W = 13.4 W

Current through the circuit, I = $\frac{V}{R_{s}}$ = $\frac{9 V}{13.4 Ω}$ = 0.67 A

In series, same current (I) flows through all the resistors. Thus, current flowing through 12 W resistor = 0.67 A

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