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Question

A battery of e.m.f. 2.2V and internal resistance 1.2Ω is connected to a potentiometer wire of length 10m and resistance 9.8Ω. The potential drop per cm of length of the wire is

A
0.196 mV
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B
9.16 m V
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C
19.6 m V
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D
1.96 m V
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Solution

The correct option is C 1.96 m V
E=I[1.2+9.8]

2.211=I

I=0.2A

P.D across potentiometer =0.2×9.8

=1.96V

P.Dlength=1.9610=0.196V/m

=0.196100V/cm

=1.96mV/cm

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