A bent wire AB carrying a current I is placed in a region of uniform magnetic field B- The force on the wire AB is LA- text B I L B- 3-2 BILC- ZeroD- BIL -2

The correct option is D BIL/2 F⃗=I(l⃗×B⃗) Here l⃗ is directed from end A to end B of the wire. Here |l⃗| = L/2 and θ = 90^∘……F = I×L/2×B = BIL/2 ...

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Standard XII

Physics

A Uniform Rod

A bent wire A...

Question

A bent wire AB carrying a current I is placed in a region of uniform magnetic field $\to B$ . The force on the wire AB is

$\text{BIL$}

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$\frac{3}{2} BIL$

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Zero

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$\frac{BIL}{2}$

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Solution

The correct option is D
$\frac{BIL}{2}$

$\to F = I (\to l \times \to B)$

Here $\to l$ is directed from end A to end B of the wire.

Here $| \to l | = \frac{L}{2}$ and $θ = 90^{\circ} \dots \dots F = I \times \frac{L}{2} \times B = \frac{BIL}{2}$

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A bent wire AB carrying a current I is placed in a region of uniform magnetic field →B. The force on the wire AB is

The correct option is D BIL2 →F=I(→l×→B) Here →l is directed from end A to end B of the wire. Here |→l|=L2 and θ=90∘……F=I×L2×B=BIL2

A bent wire AB carrying a current I is placed in a region of uniform magnetic field $\to B$ . The force on the wire AB is

The correct option is D
$\frac{BIL}{2}$

$\to F = I (\to l \times \to B)$

Here $\to l$ is directed from end A to end B of the wire.

Here $| \to l | = \frac{L}{2}$ and $θ = 90^{\circ} \dots \dots F = I \times \frac{L}{2} \times B = \frac{BIL}{2}$