A bent wire PQ carrying a current I is placed in a region of uniform magnetic field B having magnitude B- The force on the wire PQ is n - BIL-The value of n is

F=I(l×B) Here l is directed from end P nbsp;to end Q nbsp;of the wire if the current is directed from Q to P Here |l| = L/2 and θ = 90^∘ nbsp; ⇒ nbsp;F ...

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Standard XII

Physics

Magnetic Field Due to a Circular Ring on the Axis

A bent wire P...

Question

A bent wire PQ carrying a current I is placed in a region of uniform magnetic field $\to B$ having magnitude B . The force on the wire PQ is $n \times B I L$ .The value of n is

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Solution

$\to F = I (\to l \times \to B)$

Here $\to l$ is directed from end P to end Q of the wire if the current is directed from Q to P

Here $| \to l | = \frac{L}{2}$ and $θ = 90^{\circ} \Rightarrow F = I \times \frac{L}{2} \times B = \frac{BIL}{2}$
$\Rightarrow n = 0.5$

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A bent wire PQ carrying a current I is placed in a region of uniform magnetic field →B having magnitude B . The force on the wire PQ is n×BIL .The value of n is

→F=I(→l×→B) Here →l is directed from end P to end Q of the wire if the current is directed from Q to P Here |→l|=L2 and θ=90∘⇒F=I×L2×B=BIL2 ⇒n=0.5

A bent wire PQ carrying a current I is placed in a region of uniform magnetic field $\to B$ having magnitude B . The force on the wire PQ is $n \times B I L$ .The value of n is

$\to F = I (\to l \times \to B)$

Here $\to l$ is directed from end P to end Q of the wire if the current is directed from Q to P

Here $| \to l | = \frac{L}{2}$ and $θ = 90^{\circ} \Rightarrow F = I \times \frac{L}{2} \times B = \frac{BIL}{2}$
$\Rightarrow n = 0.5$