Question

A bicycle increases its velocity from 10km/h to 15km/h in 6 seconds. Calculate its acceleration.

Answer 1

Step 1: Given

Initial velocity$\text{= u = 10 km /hr}=10\times \frac{5}{18}=\frac{25}{9}$ m/sec
Final velocity $\text{= v = 15 km / hr}=15\times \frac{5}{18}=\frac{25}{6}m/sec$
Time $\text{= t = 6 sec}$
Let a is acceleration.

Step 2: Formula used
$\text{v = u + at}$ (first equation of motion)

Step 3: Finding the acceleration

v = u + at

$\frac{25}{6}$ =$\frac{25}{9}$ +a*6

a = 0.22$m{s}^{-2}$
So acceleration is, a = 0.22 $m{s}^{-2}$ .