Third Equation of Motion
Trending Questions
An object has a velocity u at time t=0, it is undergoing retardation a and covers a distance s attaining a velocity v in time t. Which of the following equations of motion correctly describe the motion?
u=v−at
s=ut+12at2
u2=2as+v2
u=v+at
A body with an initial velocity of 18kmh accelerates uniformly at the rate of 3cms2 over a distance of 200 m in t s. What will be its be its velocity at time t?
27ms
37ms
√27ms
√37ms
- False
- True
- False
- True
- a=4ms−2, t=30 s
- a=3ms−2, t=40 s
- a=3ms−2, t=30 s
- a=4ms−2, t=40 s
- 1350 m
- 1620 m
- 1700 m
- 1482 m
- 905 m
- 925 m
- 945 m
- 965 m
- 925 m
- 905 m
- 945 m
- 965 m
A body when projected up with an initial velocity u goes to a maximum height h in time t and then comes back at the point of projection.The correct statement is:
(a) the average velocity is 2ht
(b) the acceleration is zero
(c) the final velocity on reaching the point of projection is 2u.
(d) the displacement is zero.
The driver of a train traveling at 40 ms−1 applies the brakes as the train enters a station. The train slows down at a rate of 2 ms−2. The distance traveled by train before stopping is
- 200 m
- 400 m
- 300 m
- 500 m