The correct option is B 12 ms−1 , 720 m
initial speed of the bus, u=0,
acceleration, a=0.1 ms−2
and time taken, t=2 minutes=2×60=120 s
Let v be the final velocity and s be the distance covered.
(a) From the first equation of motion,v=u+at,
⇒ v=12 ms−1
(b) According to the third equation of motion, v2−u2=2as
Speed acquired by the bus is 12 ms−1 and the distance travelled is 720 m.