CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A stone is thrown vertically upward with an initial velocity of 40ms-1. Taking g=10ms-2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?


Open in App
Solution

Step 1: Given

Initial velocity (u) = 40ms-1 (in upward direction)

Final velocity (v) = 0ms-1

Acceleration due to gravity, g=10ms-2

Step 2: Formula used and calculation

v2=u2+2as0=402+2×(-10)×s

(-ve sign is used because the stone is going upward)

20s=1600s=160020s=80m

Hence, the maximum height is 80m.

Step 3: Calculation of net displacement and total distance covered

Total distance covered = 2×maximum height

=2×80m=160m

Net displacement is zero because initial position and final position are same.


flag
Suggest Corrections
thumbs-up
56
BNAT
mid-banner-image