Question

A scooter acquires a velocity of 36km/h in 10 seconds just after the start.calculate the acceleration of the car.

Answer 1

CASE 1:

Initial velocity, u = 0m/s
Final velocity, v = 36 km/hr = 10 m/s
Time, t = 10 s

Acceleration, a = (v - u) / t
∴a = (10 - 0) / 10
= 10/10
∴a = 1 m/s²

Thus, acceleration of the scooter is 1 m/s².

CASE 2:-

Initial velocity, u = 36 km/h = 10 m/s
Final velocity, v = 0 m/s
Time, t = 20 s

Acceleration, a = (v - u) / t
∴a = (0 - 10) / 20
= -10/20
∴a = - 0.5 m/s²

Thus, acceleration of the scooter is -0.5 m/s². The negative sign indicates retardation.

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