A car acquires a velocity of $72 k m h^{- 1}$ in 10 s starting from rest. Calculate the acceleration.

7.2 m s^{- 2}

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20 m s^{- 2}

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200 m s^{- 2}

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2 m s^{- 2}

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Solution

The correct option is C $2 m s^{- 2}$
$v = 72 k m / h = \frac{72 \times 1000}{3600} = 20 m / s$

Acceleration $a = \frac{v - u}{t}$
$= \frac{(20 - 0) m s^{- 1}}{10 s} = 2 m s^{- 2}$

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