Starting from rest, a car acquires a speed of $90 k m h^{- 1}$ in $10 s$ , calculate the acceleration in this case.

2.5 c m s^{- 2}

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2.5 m s^{- 2}

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2.5 m m s^{- 2}

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25 m s^{- 2}

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Solution

The correct option is B $2.5 m s^{- 2}$
Given:
$u = 0$ (since car starts from rest),
$v = 90 k m h^{- 1} = 90 \times \frac{5}{18} = 25 m s^{- 1}$

We know, from first qquation of motion as:
So, using $v = u + a t,$
and since $u = 0$

We get, $v = a t$

$a$ = $\frac{v}{t}$ = $\frac{25}{10}$ = $2.5 m s^{- 2}$

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