A bicycle initially moving with a velocity 8m/s accelerates for 6s at a rate of 4m/s^2 . What will be its final velocity

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Solution

Using the equation v=u+at
Here u=8m/sec
t=6sec
a=4m/sec^2
So
v=8+4*6
=8+24
=32 m/sec

So final velocity is 32m/sec.

Hope this helps :)

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A bicycle initially moving with a velocity 8m/s accelerates for 6s at a rate of 4m/s^2 . What will be its final velocity

Using the equation v=u+at Here u=8m/sec t=6sec a=4m/sec^2 So v=8+4*6 =8+24 =32 m/sec So final velocity is 32m/sec. Hope this helps :)

Using the equation v=u+at
Here u=8m/sec
t=6sec
a=4m/sec^2
So
v=8+4*6
=8+24
=32 m/sec

So final velocity is 32m/sec.

Hope this helps :)