A big drop of radius $R$ is formed by $1000$ small droplets of water, then the radius of small drop is

R / 2

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R / 5

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R / 6

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R / 10

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Solution

The correct option is D $R / 10$
now,
since volume is same,
$\frac{4}{3} π R^{3} = 1000 * \frac{4}{3} π r^{3}$ (As volume remains constant)
$R^{3} = 1000 r^{3} \Rightarrow R = 10 r \Rightarrow r = \frac{R}{10}$

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now,
since volume is same,
$\frac{4}{3} π R^{3} = 1000 * \frac{4}{3} π r^{3}$ (As volume remains constant)
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