Question

a bivalent has an equivalent weight 12. the molecular weight of its oxide will be

Answer 1

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$$\begin{gathered} \mathrm{Equivalent}\mathrm{weight}=\frac{\mathrm{Molecular}\mathrm{weight}}{\mathrm{Valency}} \\ \mathrm{Therefore},\mathrm{Molecular}\mathrm{Weight}=\mathrm{Equivalent}\mathrm{weight}\times \mathrm{Valency} \\ =12\times 2 \\ =24 \end{gathered}$$