A black compound of manganese reacts with a halogen acid to give a greenish yellow gas. When excess of this gas reacts with $N H_{3}$ , an unstable trihalide is formed. In this process, the oxidation state of nitrogen changes from :

- 3

+ 3

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- 3

0

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- 3

+ 5

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0

- 3

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Solution

The correct option is D $- 3$ to $+ 3$
The black compound is $M n O_{2}$ .

$M n O_{2} (b l a c k) + 4 H C l \to M n C l_{2} + C l_{2} (g r e e n i s h y e l l o w g a s) ↑ + 2 H_{2} O$

$(- 3) N H_{3} + 3 C l_{2} (e x c e s s s) \to (+ 3) N C l_{3} + 3 H C l$

The oxidation state of $N$ in $N H_{3}$ is $- 3$ .

The oxidation state of $N$ in $N C l_{3}$ is $+ 3$ .

Hence, the oxidation state of nitrogen changes from $- 3$ to $+ 3$ .
Option A.

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A black compound of manganese reacts with a halogen acid to give a greenish yellow gas. When excess of this gas reacts with NH3, an unstable trihalide is formed. In this process, the oxidation state of nitrogen changes from :

A black compound of manganese reacts with a halogen acid to give a greenish yellow gas. When excess of this gas reacts with $N H_{3}$ , an unstable trihalide is formed. In this process, the oxidation state of nitrogen changes from :