A block and tackle system has the velocity ratio 3. A man can exert a pull of 200 kgf. What is the maximum load he can raise with this pulley system if its efficiency is 50%?

300 kgf

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360 kgf

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600 kgf

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180 kgf

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Solution

The correct option is A
300 kgf

E = $\frac{1}{n (n u m b e r o f p u l l e y s)}$

200 = $\frac{L}{3}$

L = 600 kgf

Efficiency = 50% = $\frac{50}{100}$ $\times$ 600 = 300

Maximum load that can be raised = 300 kgf

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A block and tackle system have the velocity ratio 3. A man can exert a pull of 200 kgf. What is the maximum load he can raise with this pulley system if its efficiency is 50%?

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A block and tackle system has the velocity ratio 3. A man can exert a pull of 200 kgf. What is the maximum load he can raise with this pulley system if its efficiency is 50%?

The correct option is A 300 kgf E = 1n(number of pulleys) 200 = L3 L = 600 kgf Efficiency = 50% = 50100 × 600 = 300 Maximum load that can be raised = 300 kgf

The correct option is A
300 kgf

E = $\frac{1}{n (n u m b e r o f p u l l e y s)}$

200 = $\frac{L}{3}$

L = 600 kgf

Efficiency = 50% = $\frac{50}{100}$ $\times$ 600 = 300

Maximum load that can be raised = 300 kgf