A block is sliding down on an inclined plane. The velocity changes at a constant rate from $10 c m / s$ to $15 c m / s$ in $2 s e c o n d s$ . What is its acceleration?

2.5 cm/s²

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1.5 cm/s²

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4.5 cm/s²

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1.25 cm/s²

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Solution

The correct option is A
2.5 cm/s²

The motion is depicted below.

Here,
Initial velocity $u = 10 c m / s$
Final Velocity $v = 15 c m / s$
Time taken $t = 2 s$
Let $a$ be the acceleration

Using the equation of motion
$v = u + a t$

$a = \frac{v - u}{t}$

$a = \frac{15 - 10}{2}$ $c m / s^{2}$

$a = 2.5 c m / s^{2}$

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A block is sliding down on an inclined plane. The velocity changes at a constant rate from 10 cm/s to 15 cm/s in 2 seconds. What is its acceleration?

The correct option is A 2.5 cm/s2 The motion is depicted below. Here, Initial velocity u=10 cm/s Final Velocity v=15 cm/s Time taken t=2 s Let a be the acceleration Using the equation of motion v=u+at a=v − ut a=15 − 102 cm/s2 a=2.5 cm/s2

A block is sliding down on an inclined plane. The velocity changes at a constant rate from $10 c m / s$ to $15 c m / s$ in $2 s e c o n d s$ . What is its acceleration?