Question

A block of certain material has magnetization, equal to $1.2{\text{Am}}^{-1}$. If the magnetic intensity of the block is $4\times {10}^3{\text{Am}}^{-1}$, then calculate, the magnetic susceptibility of the block.

• A. $2\times {10}^{-4}$
• B. ${10}^{-4}$
• C. $3\times {10}^{-4}$
• D. $4\times {10}^{-4}$

Answer 1

The correct option is C $3\times {10}^{-4}$

We know that the relation between magnetic intensity $H$, magnetisation vector $I$ and magnetic susceptibility $\chi$ is given by,

$I=\chi H$

$\Rightarrow \chi =\frac{I}{H}$

From the data given in the question,

$\chi =\frac{1.2}{4\times {10}^3}$

$\therefore \chi =3\times {10}^{-4}$

Hence, the correct answer is option $\left(C\right)$